`**n_{Zn} = frac{m_{Zn}}M = frac{6,5}{65}=0,1 (mol)`

`PT:` `Zn + 2HCl -> ZnCl_2 +H_2↑`

          `0,1`       `0,2`              `0,1`        `0,1` `(mol)`

`->m_{HCl}= D.V_{dd HCl}= 1,18*150=177(gam)`

`mdd_S=m_{Zn} + mdd_{HCl}- m_{H_2}`

           `=6,5+177-(0,1*2)`

           `= 183,3(g)`

`C%ZnCl_2=frac{n*M*100}{mdd_S}=frac{0,1*136*100}{183,3}=7,42%`

#ntp:33

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