Đáp án:

`(2x-1)^6 = (2x-1)^10`
`=>(2x-1)^10 -(2x-1)^6=0`
`=>(2x-1)^6 * (2x-1)^4 -(2x-1)^6=0`
`=>(2x-1)^6 *[(2x-1)^4 -1]=0`
`=>` $\left[\begin{matrix} (2x-1)^6 =0\\ (2x-1)^4 -1=0\end{matrix}\right.$
`=>` $\left[\begin{matrix} 2x-1=0\\ (2x-1)^4=1\end{matrix}\right.$
`=>` $\left[\begin{matrix} 2x-1=0\\ 2x-1=1\\ 2x-1=-1\end{matrix}\right.$
`=>` $\left[\begin{matrix} x=\dfrac{1}{2}\\ x=1\\ x=0\end{matrix}\right.$
Vậy: `x in {1/2;1;0}`