Đáp án:

$\rm c)\\ CH_3COOC_2H_5+H_2O\xrightarrow{Acid ,\ t^°}CH_3COOH+C_2H_5OH\\CH_3COOH+Na\to CH_3COONa+\dfrac{1}{2}H_2\\CH_3COONa+HCl\to CH_3COOH+NaCl\\2CH_3COOH+Zn\to (CH_3COO)_2Zn+H_2\\d)\\ C_2H_4+H_2O\xrightarrow{H_2SO_4\ (dac),\ t^°}C_2H_5OH\\C_2H_5OH+CH_3COOH\overset{H_2SO_4\ (dac),\ t^°}\leftrightarrows CH_3COOC_2H_5+H_2O\\CH_3COOC_2H_5+H_2O\xrightarrow{Acid ,\ t^°}CH_3COOH+C_2H_5OH\\2CH_3COOH+Ca\to (CH_3COO)_2Ca+H_2$