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Đáp án:
$\rm 4)\ CH_2=CH_2+Br_2\to CH_2Br-CH_2Br\\5)\ C_2H_6O+3O_2\xrightarrow{t^°}2CO_2+3H_2O\\6)\ C_2H_5OH+Na\to C_2H_5ONa+\dfrac{1}{2}H_2\\7)\ C_2H_4+H_2O\xrightarrow{H_2SO_4\ (conc.),\ t^°}C_2H_5OH\\8)\ CH_3COOH+NaOH\to CH_3COONa+H_2O\\9)\ 2CH_3COOH+CuO\to (CH_3COO)_2Cu+2H_2O\\10)\ 2CH_3COOH+Mg\to (CH_3COO)_2Mg+H_2\\11)\ 2CH_3COOH+CaCO_3\to (CH_3COO)_2Ca+CO_2+H_2O\\12)\ CH_3COOH+C_2H_5OH\overset{H_2SO_4\ (conc. ),\ t^°}\leftrightarrows CH_3COOC_2H_5+H_2O\\13)\ 2C_4H_{10} + 5O_2\xrightarrow{t^°,\ xt }4CH_3COOH + 2H_2O\\14)\ C_2H_5OH+O_2\xrightarrow{men,\ t^°}CH_3COOH+H_2O\\15)\ (RCOO)_3C_3H_5+3H_2O\overset{H^+,\ t^°}\leftrightarrows 3RCOOH+C_3H_5(OH)_3\\16)\ (RCOO)_3C_3H_5+3NaOH\xrightarrow{t^°}3RCOONa+C_3H_5(OH)_3\\17)\ C_2H_2+\dfrac{5}{2}O_2\xrightarrow{t^°}2CO_2+H_2O\\18)\ C_2H_2+2Br_2\to C_2H_2Br_4$
Hãy giúp mọi người biết câu trả lời này thế nào?
$\rm 4.CH_2=CH_2+Br_2 \xrightarrow{} CH_2Br-CH_2Br$
$\rm 5.C_2H_5OH+3O_2 \xrightarrow{} CO_2+3H_2O$
$\rm 6.2C_2H_5OH+2Na \xrightarrow{} 2C_2H_5ONa+H_2$
$\rm 7.C_2H_4+H_2O \xrightarrow{t^o,H_2SO_4 đ} C_2H_5OH$
$\rm 8.CH_3COOH+NaOH \xrightarrow{} CH_3COONa+H_2O$
$\rm 9.2CH_3COOH+CuO \xrightarrow{} (CH_3COO)_2Cu+2H_2O$
$\rm 10.2CH_3COOH+Mg \xrightarrow{} (CH_3COO)_2Mg+H_2$
$\rm 11.2CH_3COO+CaCO_3 \xrightarrow{} (CH_3COO)_2Ca+CO_2+2H_2O$
$\rm 12. CH_3COOH+C_2H_5OH \buildrel{{H_2SO_4đ,t^o}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$
$\rm 13.2C_4H_{10}+5O_2 \xrightarrow{t^o,xt} 4CH_3COOH+2H_2O$
$\rm 14.C_2H_5OH+O_2 \xrightarrow{man giấm.t^o} CH_3COOH+H_2O$
$\rm 15.(RCOO)_3C_3H_5+3H_2O \xrightarrow{H^+,t^o} C_3H_5(OH)_3+3RCOOH$
$\rm 16.(RCOO)_3C_3H_5+3NaOH \xrightarrow{} 3RCOONa+C_3H_5(OH)_3$
$\rm 17.2C_2H_2+5O_2 \xrightarrow{t^o} 4CO_2+2H_2O$
$\rm 18.C_2H_2+2Br_2 \xrightarrow{} C_2H_2Br_4$
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https://hoidap247.com/cau-hoi/6956409
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https://hoidap247.com/cau-hoi/6956412
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