$\rm V_{C_2H_5OH}=\dfrac{V_r \times Đ_r}{100}(L)=V_r \times Đ_r \times 10(mL) $

`=>`$\rm m_{C_2H_5OH}= V_{C_2H_5OH}  \times d =V_r \times Đ_r \times 10 \times d(gam)$

`=>`$\rm n_{C_2H_5OH}=\dfrac{m_{C_2H_5OH}}{M_{C_2H_5OH}}=\dfrac{V_r \times Đ_r \times 10 \times d}{M_{C_2H_5OH}}(mol)$

$\rm C_6H_{12}O_6 \xrightarrow[\%H=80\%]{enzim}2CO_2+2C_2H_5OH$

`=>`$\rm n_{glucose}=\dfrac{1}{2} n_{C_2H_5OH} \times \dfrac{1}{\%H}$

$\rm =\dfrac{1}{2} \times \dfrac{V_r \times Đ_r \times 10 \times d}{M_{C_2H_5OH}} \times \dfrac{1}{\%H}(mol)$

`=>`$\rm m_{glucose}=n_{glucose} \times M_{glucosee}$

$\rm =\dfrac{1}{2} \times \dfrac{V_r \times Đ_r \times 10 \times d}{M_{C_2H_5OH}} \times \dfrac{1}{\%H} \times M_{glucose}$

$\rm =\dfrac{1}{2} \times \dfrac{500 \times 12 \times 10 \times 0.8}{46} \times \dfrac{1}{0.8} \times 180$

$\rm =\dfrac{2700000}{23}(gam)$

$\rm ≈117(kg)$