\(\begin{array}{|c|c|c|}\hline &\text{Mệnh đề} &Đ&S\\\hline a)&30^o=\dfrac{\pi}{6} rad&\times&\\\hline b)&\left(\dfrac{15}{\pi}\right)^o=\dfrac{1}{12}rad&\times&\\\hline c)&132^o=\dfrac{11\pi}{15}rad&\times&\\\hline\ d)&-485^o=\dfrac{13\pi}{4}rad&&\times\\\hline\end{array}\\1^o\longrightarrow \dfrac{\pi}{180}rad\\a)\\\Rightarrow 30^o=30.\dfrac{\pi}{180}=\dfrac{\pi}{6}rad\\\longrightarrow D\\b)\\\left(\dfrac{15}{\pi}\right)^o=\dfrac{15}{\pi}.\dfrac{\pi}{180}=\dfrac{1}{12}rad\\\longrightarrow D\\c)\\132^o=132.\dfrac{\pi}{180}=\dfrac{11\pi}{15}\\\longrightarrow D\\d)\\-495^o=-495.\dfrac{\pi}{180}=-\dfrac{11\pi}{4}\\\longrightarrow S\)