Đáp án:

Bài 2:

$b) C_6H_{12}O_6 \xrightarrow{men} 2C_2H_5OH + 2CO_2$

=> Khí thoát ra

`e) 2CH_3COOH + Na_2CO_3 \to 2CH_3COONa + CO_2 + H_2O`

=> Dung dịch sủi bọt khí không màu

Bài 4:

`2CH_3COOH + 2Na \to 2CH_3COONa + H_2`

`2C_2H_5OH + 2Na \to 2C_2H_5ONa + H_2`

`CH_3COOH + KOH \to CH_3COOK + H_2O`

`2CH_3COOH + Na_2CO_3 \to 2CH_3COONa + CO_2 + H_2O`

Bài 5:

`a)`

$nCH_2=CH_2 \xrightarrow{t^0,xt,P} (-CH_2-CH_2-)_n$

$C_2H_4 + H_2O \xrightarrow{t^0,H^{+}} C_2H_5OH$

`C_2H_5OH + O_2 \to CH_3COOH + H_2O`

`CH_3COOH + NaOH \to CH_3COONa + H_2O`

`d)`

`C_2H_4 + Br_2 \to C_2H_4Br_2`

$C_2H_4 + H_2O \xrightarrow{t^0,H^{+}} C_2H_5OH$

$C_2H_5OH + CH_2COOH$ $\buildrel{{{t^0, H_2SO_4đ}}}\over\rightleftharpoons$ $CH_3COOC_2H_5 + H_2O$