`n_X=n_{N_2}={1,68}/{28}=0,06(mol)`

`X:CH_3OH:x(mol);HCOOCH_3:y(mol);HCHO:z(mol)`

`->x+y+z=0,06(1)`

BTNT C: `x+2y+z=n_{CO_2}={1,68}/{22,4}=0,075(2)`

BTNT H: `2x+2y+z=n_{H_2O}={1,71}/{18}=0,095(3)`

`(1)(2)(3)->x=0,02;y=0,015;z=0,025`

`->m=0,02.32+0,015.60+0,025.30=2,29(g)`

`{m_2}/m={3,435}/{2,29}=1,5`

`->` TN2 chứa `n_{CH_3OH}=0,03(mol);n_{HCOOCH_3}=0,0225(mol);n_{HCHO}=0,0375(mol)`

`HCHO+4[Ag(NH_3)_2]OH->(NH_4)_2CO_3+4Ag+6NH_3+2H_2O`

`HCOOCH_3+2[Ag(NH_3)_2]OH->NH_4OCOOCH_3+2Ag+3NH_3+H_2O`

`->n_{Ag}=2n_{HCOOCH_3}+4n_{HCHO}=0,195(mol)`

`->m=0,195.108=21,06(g)`