`2X+O_2` $\xrightarrow{t^o}$ `2XO`

`4Y+3O_2` $\xrightarrow{t^o}$ `2Y_2O_3`

BTKL: `n_{O_2}={4,88-2,64}/{32}=0,07(mol)`

`->0,5n_X+0,75n_Y=n_{O_2}=0,07(mol)`

`n_X=1/4n_Y`

`->n_X=0,02(mol);n_Y=0,08(mol)`

`m_{hh}=0,02M_X+0,08M_Y=2,64(g)`

`->M_X+4M_Y=132(1)`

`{M_X}/{M_Y}=8/9`

`->9M_X-8M_Y=0(2)`

`(1)(2)->M_X=24(Mg);M_Y=27(Al)`

X: magnesium

Y: aluminium