(x-3)(y+1) = 7 (4-x)(y+3)=-3 giải nhanh nhé mình sẽ chấm 5 sao hứa là làm

$(x-3)(y+1)=7$

⇔ \(\left[ \begin{array}{l}x-3=1\\y+1=7\\x-3=7\\y+1=1\end{array} \right.\)

⇔ \(\left[ \begin{array}{l}x=4\\y=6\\x=10\\y=0\end{array} \right.\)

⇔ \(\left[ \begin{array}{l}x=-1\\y=-7\\x=1\\y=7\end{array} \right.\)

$(4-x)(y+3)=-3$

⇔ \(\left[ \begin{array}{l}4-x=1\\y+3=-3\\y+3=1\\4-x=-3\end{array} \right.\) 

⇔ \(\left[ \begin{array}{l}x=3\\y=-6\\y=-2\\x=7\end{array} \right.\)     

⇔ \(\left[ \begin{array}{l}x=-1\\x=1\end{array} \right.\) 

⇔ \(\left[ \begin{array}{l}x=-3\\x=3\end{array} \right.\) 

⇔ \(\left[ \begin{array}{l}y=1\\y=-1\end{array} \right.\) 

⇔ \(\left[ \begin{array}{l}y=3\\y=-3\end{array} \right.\)