Bài 2: (2 điểm) Tìm x biết a)  $(x-\frac{1}{4})$ + $\frac{-3}{4}$= $\frac{3}{8}$  b) $\frac{x}{-8}-1 = $ $\frac{-1}{2}$  c) $(x+ \frac{4}{5})$ $(\frac{1}{3}-x) = 0$  d) $(\frac{3}{2}-x)^2+$ $\frac{1}{5}= $ $\frac{3}{4}$. $\frac{8}{25}$ 

Bài `2:`

`a)(x-1/4)+(-3)/4=3/8`

`=>x-1/4=3/8-(-3/4)`

`=>x-1/4=9/8`

`=>x=9/8+1/4`

`=>x=11/8`

Vậy `x=11/8`

`b)x/-8-1=(-1)/2`

`=>-x/8=-1/2+1`

`=>-x/8=1/2`

`=> -x.2=8.1`

`=>-x.2=8`

`=> -x=8:2`

`=>-x=4`

`=>x=-4`

Vậy `x=-4`

`c)(x+4/5)(1/3-x)=0`

`=>` `x+4/5=0` hoặc `1/3-x=0`

`=>x=0-4/5` hoặc `x=0+1/3`

`=>x=-4/5` hoặc `x=1/3`

Vậy `x in {-4/5;1/3}`

`d)(3/2-x)^2+1/5=3/4. 8/25`

`=>(3/2-x)^2+1/5=6/25`

`=>(3/2-x)^2=6/25-1/5`

`=>(3/2-x)^2=6/25-5/25`

`=>(3/2-x)^2=1/25`

`=> (3/2-x)^2=1/5^2` hoặc `(3/2-x)^2=(-1/5)^2`

`=>` `3/2-x=1/5` hoặc ` 3/2-x=-1/5`

`=> x=3/2-1/5` hoặc `x=3/2+1/5`

`=>x=13/10` hoặc `x=17/10`

Vậy `x in {13/10 ; 17/10}`