giúp e với ạ ạ cảm ơn

`a)x+`$\frac{1}{3}$`=`$\frac{2}{5}$`-(-`$\frac{1}{3}$`)`

`⇒x+`$\frac{1}{3}$`=`$\frac{2}{5}$`+`$\frac{1}{3}$

`⇒x=`$\frac{2}{5}$`+`$\frac{1}{3}$`-`$\frac{1}{3}$

`⇒x=`$\frac{2}{5}$

Vậy `x=`$\frac{2}{5}$

`b)`$\frac{x-1}{x+5}$`=`$\frac{6}{7}$

`⇒7(x-1)=6(x+5)`

`⇒7x-7=6x+30`

`⇒7x-7-6x-30=0`

`⇒x-37=0`

`⇒x=37`

Vậy `x=37`