(x-1)x(x+1)(x+2)-24=0 Tìm x ạ giúp vs

Đáp án `+` Giải thích các bước giải:

`(x-1)x(x+1)(x+2)-24=0`

`<=>(x-1)(x+1)x(x+2)-24=0`

`<=> (x^2-1)(x^2+2x)-24=0`

`<=> x^4 + 2x^3 - x^2 - 2x - 24 =0`

`<=> x^4 - 2x^3  + 4x^3 - 8x^2 + 7x^2 - 14x + 12x - 24=0`

`<=> x^3(x-2) + 4x^2(x-2) + 7x(x-2) + 12(x-2)=0`

`<=> (x^3+4x^2+7x+12)(x-2)=0`

`<=> [x^2(x+3)+x(x+3)+4(x+3)](x-2)=0`

`<=>(x^2+x+4)(x+3)(x-2)=0`

`<=>` $\left[\begin{matrix}x+3=0\\x-2=0\end{matrix}\right.$

`<=>` $\left[\begin{matrix} x=-3\\x=2\end{matrix}\right.$

Vậy `x ∈ {-3;2}`.