Viết PTHH Theo sơ đồ chuyển hóa sau: 1. C2H4-->C2H5OH-->CH3COOH-->(CH3COO)2Zn 2. Glucozơ--> rượu etylic-->axit Axetic--> natri axetat 3. C4H10-->CH3COOH-->CH3COOC2H5-->CH3COONa

Đáp án:

Giải thích các bước giải:

$1/$

$C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH$

$C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$

$2CH_3COOH + Zn → (CH_3COO)_2Zn + H_2$

$2/$

$C_6H_{12}O_6 \xrightarrow{t^o,men\ rượu} 2CO_2 + 2C_2H_5OH$

$C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$

$CH_3COOH + NaOH → CH_3COONa + H_2O$
$3/$

$C_4H_{10} +2,5 O_2 \xrightarrow{t^o,xt} 2CH_3COOH + H_2O$

$CH_3COOH + C_2H_5OH \buildrel{{H^+}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$

$CH_3COOC_2H_5 + NaOH → CH_3COONa + C_2H_5OH$