C2H5OH + K2Cr2O7 + H2SO4 -> K2SO4 + CO2 + Cr2(SO4)3 + H2O thăng bằng e

$\mathop{C}\limits^{-3}H_3\mathop{C}\limits^{-1}H_2OH+K_2\mathop{Cr_2}\limits^{+6}O_7+H_2SO_4 \to K_2SO_4+\mathop{C}\limits^{+4}O_2+\mathop{Cr_2}\limits^{+3}(SO_4)_3+H_2O$

$\text{ 1 x | }$$\mathop{C}\limits^{-3}+\mathop{C}\limits^{-1} \to \mathop{2C}\limits^{+4}+12e^-$

$\text{ 2 x | }$$\mathop{2Cr}\limits^{+6}+6e^- \to \mathop{2Cr}\limits^{+3}$

`->`$C_2H_5OH+2K_2Cr_2O_7+8H_2SO_4 \to 2K_2SO_4+2CO_2+2Cr_2(SO_4)_3+11H_2O$