giúp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Đáp án+Giải thích các bước giải:

$\frac{x+2}{327}$ + $\frac{x+3}{326}$ + $\frac{x+4}{325}$ + $\frac{x+5}{324}$ + $\frac{x+349}{5}$ = 0

⇔ ($\frac{x+2}{327}$ + 1) + ($\frac{x+3}{326}$ + 1) + ($\frac{x+4}{325}$ + 1) + ($\frac{x+5}{324}$ + 1) + ($\frac{x+349}{5}$ - 4) = 0

⇔ ($\frac{x+2}{327}$ + $\frac{327}{327}$) + ($\frac{x+3}{326}$ + $\frac{326}{326}$) + ($\frac{x+4}{325}$ + $\frac{325}{325}$)  + ($\frac{x+5}{324}$ + $\frac{325}{325}$) + ($\frac{x+349}{5}$ - $\frac{20}{5}$) = 0

⇔ $\frac{x+329}{327}$ + $\frac{x+329}{326}$ + $\frac{x+329}{325}$ + $\frac{x+329}{324}$ + $\frac{x+329}{5}$ = 0

⇔ (x + 329)($\frac{1}{327}$ + $\frac{1}{326}$ + $\frac{1}{325}$ + $\frac{1}{324}$ + $\frac{1}{5}$) = 0

Do $\frac{1}{327}$ + $\frac{1}{326}$ + $\frac{1}{325}$ + $\frac{1}{324}$ + $\frac{1}{5}$ > 0

⇒ x + 329 = 0

⇔ x = -329

Vậy x = -329

@tuan789