Để cực dễ luôn Á nên mm giúp em với

`a)`

`C_6H_{12}O_6`  $\xrightarrow{t^o,enzyme}$  `2C_2H_5OH+2CO_2`

`n_{C_6H_{12}O_6\ l t}={1.1000}/{180}={50}/9(mol)`

Theo pt:

`n_{C_2H_5OH\ l t}=2n_{C_6H_{12}O_6\ l t}={100}/9(mol)`

`m_{C_2H_5OH\ t t}={100}/{9}.65\%.46=332,22(g)`

`b)`

`V_{C_2H_5OH}={332,22}/{0,8}=415,275(mL)`

`V_r={415,275.100}/{23}=1805,54(mL)`

`c)`

`n_{C_6H_{12}O_6\ l t}={50}/{9}.1/{10}=5/9(mol)`

`C_6H_{12}O_6+Ag_2O` $\xrightarrow{NH_3}$ `C_6H_{12}O_7+2Ag`

Theo pt:

`n_{Ag\ l t}=2n_{C_6H_{12}O_6\ l t}={10}/9(mol)`

`m_{Ag\ t t}={10}/{9}.108.80\%=96(g)`