$\frac{2-8^{x}-3}{2^{x}}$

`lim \frac{2 - 8^{x} - 3}{2^{x}}`

`= lim [2.(\frac{1}{2})^{x} - 4^{x} - 3.(\frac{1}{2})^{x}]`

`= lim (-4^{x}) = -\infty`

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