Sos sos sos sos sos sos sos

Đáp án:

 x = 2023

Giải thích các bước giải:

$\frac{x+1}{2024}$ + $\frac{x+2}{2023}$ = $\frac{x+3}{2026}$ + $\frac{x+4}{2027}$

<=> ($\frac{x+1}{2024}$ - 1) + ($\frac{x+2}{2023}$ - 1) = ($\frac{x+3}{2026}$ - 1) + ($\frac{x+4}{2027}$ - 1)
<=> $\frac{x-2023}{2024}$ + $\frac{x-2023}{2023}$ - $\frac{x-2023}{2026}$ - $\frac{x-2023}{2027}$ = 0

<=> (x-2023)($\frac{1}{2024}$ + $\frac{1}{2025}$ - $\frac{1}{2026}$ - $\frac{1}{2027}$) = 0

<=> x - 2023=0

<=> x = 2023
Vậy x = 2023