Giải phương trình: `\sqrt{\frac{1}{3x + 2}} - \frac{1}{2}\sqrt{\frac{9}{3x + 2}} + \sqrt{\frac{16}{3x + 2}} - 5\sqrt{\frac{1}{12x + 8}} = 1`

`\sqrt(1/(3x+2))-1/2\sqrt(9/(3x+2))+\sqrt(16/(3x+2))-5\sqrt(1/(12x+8))=1`          `ĐKXĐ:x>(-2)/3`

`<=>\sqrt(1/(3x+2))-1/2\sqrt(9. 1/(3x+2))+\sqrt(16. 1/(3x+2))-5\sqrt(1/(4(3x+2)))=1`

`<=>\sqrt(1/(3x+2))-1/2\sqrt(9. 1/(3x+2))+\sqrt(16. 1/(3x+2))-5\sqrt(1/4. 1/(3x+2))=1`

`<=>\sqrt(1/(3x+2))-1/2. 3\sqrt(1/(3x+2))+4\sqrt(1/(3x+2))-5. 1/2\sqrt(1/(3x+2))=1`

`<=>\sqrt(1/(3x+2))-3/2\sqrt(1/(3x+2))+4\sqrt(1/(3x+2))-5/2\sqrt(1/(3x+2))=1`

`<=>\sqrt(1/(3x+2))=1`

`<=>(\sqrt(1/(3x+2)))^2=1^2`

`<=>1/(3x+2)=1`

`<=>1=3x+2`

`<=>-1=3x`

`<=>x=(-1)/3(TM)`

`Vậy` `S={(-1)/3}`