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`a)`

`\overline{M_H}={1.99,984+2.0,016}/{100}=1,00016(u)`

`\overline{M_{Cl}}={35.75,53+37.24,47}/{100}=35,4894(u)`

`b)`

Có 4 loại phân tử `HCl` tạo thành:

\(_1^{1}H_{17}^{35}Cl\)

\(_1^{2}H_{17}^{35}Cl\)

\(_1^{1}H_{17}^{37}Cl\)

\(_1^{2}H_{17}^{37}Cl\)

`c)`

\(M_{_1^{1}H_{17}^{35}Cl}=1+35=36(u)\)

\(M_{_1^{2}H_{17}^{35}Cl}=2+35=37(u)\)

\(M_{_1^{1}H_{17}^{37}Cl}=1+37=38(u)\)

\(M_{_1^{2}H_{17}^{37}Cl}=2+37=39(u)\)