Lập Phương Trình Hóa Học

Đáp án:

$\rm 51)\ C_nH_{2n}+\dfrac{3n}{2}O_2\xrightarrow{t^°}nCO_2+nH_2O\\52)\ C_nH_{2n+2}+\bigg(\dfrac{3n+1}{2}\bigg)O_2\xrightarrow{t^°}nCO_2+(n+1)H_2O\\53)\ C_nH_{2n-2}+\bigg(\dfrac{3n-1}{2}\bigg)O_2\xrightarrow{t^°}nCO_2+(n-1)H_2O\\54)\ 2C_nH_{2n-6}+(3n-3)O_2\xrightarrow{t^°}2nCO_2+(2n-6)H_2O\\55)\ C_nH_{2n+2}O+\dfrac{3n}{2}O_2\xrightarrow{t^°}nCO_2+(n+1)H_2O\\56)\ C_xH_y+\bigg(x+\dfrac{y}{4}\bigg)O_2\xrightarrow{t^°}xCO_2+\dfrac{y}{2}H_2O\\57)\ C_xH_yO_z+\bigg(x+\dfrac{y}{4}-\dfrac{z}{2}\bigg)O_2\xrightarrow{t^°}xCO_2+\dfrac{y}{2}H_2O\\58)\ C_xH_yO_zN_t+\bigg(x+\dfrac{y}{4}-\dfrac{z}{2}\bigg)O_2\xrightarrow{t^°}xCO_2+\dfrac{y}{2}H_2O+\dfrac{t}{2}N_2\\59)\ CH_x+\bigg(1+\dfrac{x}{4}\bigg)O_2\xrightarrow{t^°}CO_2+\dfrac{x}{2}H_2O\\60)\ FeCl_x+\bigg(\dfrac{3-x}{2}\bigg)Cl_2\xrightarrow{t^°}FeCl_3$