Bài 2 (1,5 a) $\frac{2}{3}$ + x = $\frac{-1}{12}$ b) (2x - $\frac{4}{3}$)(1 + $\frac{6}{5}$x) = 0 c) 2|x - $\frac{1}{3}$| + $\frac{7}{4}$ = $(-\frac{3}{2})^{6}$ : $(-\frac{3}{2})^{4}$điểm). Tìm x, biết:

a) `2/3 + x = (-1)/12`

`=> x = (-1)/12 - 2/3`

`=> x = (-1)/12 - 8/12`

`=> x = (-9)/12`

`=> x = (-3)/4`

Vậy, `x = (-3)/4`

b) `(2x - 4/3)(1 + 6/5x) = 0`

`=> 2x - 4/3 = 0` hoặc `1 + 6/5x = 0`

TH1: `2x - 4/3 = 0`

`=> 2x = 4/3`

`=> x = 4/3 : 2`

`=> x = 4/3 . 1/2`

`=> x = 4/6 = 2/3`

TH2: `1 + 6/5x = 0`

`=> 6/5x = -1`

`=> x = -1 : 6/5`

`=> x = -1 . 5/6`

`=> x = -5/6`

Vậy, `x in {2/3; -5/6}`

c) `2 |x - 1/3| + 7/4 = (-3/2)^6 : (-3/2)^4`

`=> 2 |x - 1/3| + 7/4 = (-3/2)^2`

`=> 2 |x - 1/3| + 7/4 = 9/4`

`=> 2 |x - 1/3| = 9/4 - 7/4`

`=> 2 |x - 1/3| = 2/4 = 1/2`

`=> |x - 1/3| = 1/2 : 2`

`=> |x - 1/3| = 1/4`

`=> x - 1/3 = 1/4` hoặc `x - 1/3 = -1/4`

TH1: `x - 1/3 = 1/4`

`=> x = 1/4 + 1/3`

`=> x = 3/12 + 4/12`

`=> x = 7/12`

TH2: `x - 1/3 = -1/4`

`=> x = -1/4 + 1/3`

`=> x = =3/12 + 4/12`

`=> x = 1/12`

Vậy, `x in {7/12; 1/12}`