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Giải thích các bước giải:

1.Ta có:

$\dfrac13x+\dfrac25(x+1)=0$

$\to \dfrac13x+\dfrac25x+\dfrac25=0$

$\to \dfrac{11}{15}x+\dfrac25=0$

$\to \dfrac{11}{15}x=-\dfrac25$

$\to x=-\dfrac6{11}$

2.Ta có:

$2x+\dfrac15(x-5)=\dfrac{17}5$

$\to 10x+(x-5)=17$

$\to 11x-5=17$

$\to 11x=22$
$\to x=2$

3.Ta có:

$4x-(2x+1)=3-\dfrac13+x$

$\to 2x-1=x+\dfrac83$

$\to x=1+\dfrac83$

$\to x=\dfrac{11}3$

4.Ta có:
$\dfrac12x+\dfrac12(x-2)=\dfrac34-2x$

$\to \dfrac12x+\dfrac12x-1=\dfrac34-2x$

$\to x-1=\dfrac34-2x$

$\to 3x=\dfrac74$

$\to x=\dfrac7{12}$