Cần giúp gấp, anh em làm nhanh nhé! Thanks

`C=1-1/2+1/3-1/4+...+1/2021-1/2022`

`C=(1+1/3+...+1/2021)-(1/2+1/4+...+1/2022)`

`C=(1+1/2+1/3+1/4+...+1/2021+1/2022)-2(1/2+1/4+...+1/2022)`

`C=(1+1/2+1/3+1/4+...+1/2021+1/2022)-(1+1/2+...+1/1011)`

`C=1/1012+1/1013+...+1/2022`

`to C-D=(1/1012+1/1013+...+1/2022)-( 1/1012+1/1013+...+1/2022)`

`to C=0`

`to (C-D)^2021=0`

`to (C-D)^2021+2022=2022`

Vậy `(C-D)^2021+2022=2022`