Giúp em với ạaaaa

1.

`a)`

`d_{\text{khí}//H_2}={M_{khí}}/2=14`

`->M_{\text{khí}}=14.2=28(a m u)`

`b)`

`d_{\text{khí}//H_2}={M_{khí}}/2=8,5`

`->M_{\text{khí}}=8,5.2=17(a m u)`

`c)`

`d_{\text{khí}//H_2}={M_{khí}}/2=17`

`->M_{\text{khí}}=17.2=34(a m u)`

`d)`

`d_{\text{khí}//H_2}={M_{khí}}/2=22`

`->M_{\text{khí}}=22.2=44(a m u)`

2.

`a)`

`d_{\text{khí}//kk}={M_{khí}}/{29}=2,207`

`->M_{\text{khí}}=2,207.29\approx 64(a m u)`

`b)`

`d_{\text{khí}//kk}={M_{khí}}/{29}=1,172`

`->M_{\text{khí}}=1,172.29\approx 34(a m u)`

3.

`a)`

`n_{\text{khí}}={4,48}/{22,4}=0,2(mol)`

`->M_{\text{khí}}={3,4}/{0,2}=17(a m u)`

`b)`

`d_{\text{khí}//kk}={M_{khí}}/{29}={17}/{29}\approx 0,586`

`d_{\text{khí}//CO_2}={M_{khí}}/{44}\approx 0,386`

4.

`M_A=2M_{CH_4}=2.16=32(a m u)`

`n_A=n_{CH_4}={6,72}/{22,4}=0,3(mol)`

`->m_A=0,3.32=9,6(g)`

        `m_{CH_4}=0,3.16=4,8(g)`

5.

`n_{CO_2}=n_X={11,2}/{22,4}=0,5(mol)`

`->m_{CO_2}=0,5.44=22(g)`

`->m_X=22-5=16(g)`

`->M_X={16}/{0,5}=32(a m u)`