4.x^2 + 6/17 .x =0 SOS Ạ

`#29042009`

`4 . x^2 +6/17 . x=0`

`<=>x(4x+6/17)=0`

`<=>` $\left[\begin{matrix} x=0\\ 4x+\dfrac{6}{17}=0\end{matrix}\right.$

`<=>` $\left[\begin{matrix} x=0\\ 4x=\dfrac{-6}{17}\end{matrix}\right.$

`<=>` $\left[\begin{matrix} x=0\\ x=\dfrac{-3}{34}\end{matrix}\right.$

vậy `x in { 0 ; -3/34}`