Mng ơi giúp e vs ạ !!!..

Đáp án:

a) ta có : $\widehat{M_1}$ + $\widehat{M_2}$ + $\widehat{M_3}$ = $\widehat{NMQ}$

$15^\circ$ + $\widehat{M_2}$ + $30^\circ$ = $90^\circ$ 

$\widehat{M_2}$ = $90^\circ$ - $30^\circ$ - $15^\circ$ 

$\widehat{M_2}$ = $45^\circ$

vậy $\widehat{AMC}$ = $45^\circ$

b) vì $15^\circ$ < $30^\circ$ < $45^\circ$

⇒ $\widehat{M_1}$ < $\widehat{M_3}$ < $\widehat{M_2}$