Huhuu giúp e với e đang cần gấp

`a)`

`m_S=6000.0,8\%=48(tan)=48.10^{6}(g)`

`->n_S={48.10^{6}}/{32}=1,5.10^6(mol)`

`->V_S=1,5.10^{6}.24,79=3,7185.10^{7}(l)`

`b)`

`n_{S(chuyen\ hoa)}=1,5.10^{6}.1\%=1,5.10^{4}(mol)`

Bảo toàn S: `n_{H_2SO_4}=n_S=1,5.10^{4}(mol)`

`->V_{ n u oc\  m u a\ nhiem\ acid}={1,5.10^4}/{1.10^{-5}}=1,5.10^{9}(l)`