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`a)(x-1)(5x+3)=(3x-8)(x-1)`

`⇔(x-1)(5x+3)-(3x-8)(x-1)=0`

`⇔(x-1)(2x+11)=0`

`⇔`$\left[\begin{matrix} 2x+11=0\\ x-1=0\end{matrix}\right.$

`⇔`$\left[\begin{matrix} x=-(11)/2\\ x=1\end{matrix}\right.$

`b)3x(25x+15)-35(5x+3)=0`

`⇔15x(5x+3)-35(5x+3)=0`

`⇔(5x+3)(15x-35)=0`

`⇔`$\left[\begin{matrix} 5x+3=0\\ 15x-35=0\end{matrix}\right.$

`⇔`$\left[\begin{matrix} x=-3/5\\ x=7/3\end{matrix}\right.$

`c)(2-3x)(x+11)=(3x-2)(2-5x)`

`⇔(2-3x)(x+11)+(2x-3)(2-5x)=0`

`⇔(2-3x)(-4x+13)=0`

`⇔`$\left[\begin{matrix} -4x+13=0\\ 2-3x=0\end{matrix}\right.$

`⇔`$\left[\begin{matrix} x=(13)/4\\ x=2/3\end{matrix}\right.$

`d)(2x^2+1)(4x-3)=(2x^2+1)(x-12)`

`⇔(2x^2+1)(4x-3)-(2x^2+1)(x-12)=0`

`⇔(2x^2+1)(3x+9)=0`

`⇔`$\left[\begin{matrix}2x^2+1=0\\ 3x+9=0\end{matrix}\right.$

`⇔`$\left[\begin{matrix}x^2=-1/2(l)\\ x=-3\end{matrix}\right.$

`e)(2x-1)^2+(2-x)(2x-1)=0`

`⇔(2x-1)(x+1)=0`

`⇔`$\left[\begin{matrix}2x-1=0\\ x+1=0\end{matrix}\right.$

`⇔`$\left[\begin{matrix}x=1/2\\ x=-1\end{matrix}\right.$

`f)(x+2)(3-4x)=x^2+4x+4`

`⇔(x+2)(3-4x)-(x+2)^2=0`

`⇔(x+2)(-5x+1)=0`

`⇔`$\left[\begin{matrix}-5x+1=0\\ x+2=0\end{matrix}\right.$

`⇔`$\left[\begin{matrix}x=1/5\\ x=-2\end{matrix}\right.$