giúp mình ạ, mình cảm ơn

Đáp án`+`Giải thích các bước giải:

`A=(sqrt{2-sqrt{3}})/sqrt{2}+(sqrt{3}-1)/2`

`A=(sqrt{2}. sqrt{2-sqrt{3}})/(sqrt{2}. sqrt{2})+(sqrt{3}-1)/2`

`A=sqrt{2(2-sqrt{3})}/2+(sqrt{3}-1)/2`

`A=(sqrt{4-2sqrt{3}}+sqrt{3}-1)/2`

`A=(sqrt{3-2sqrt{3}+1}+sqrt{3}-1)/2`

`A=(sqrt{(sqrt{3})^2-2. sqrt{3}. 1+1^2}+sqrt{3}-1)/2`

`A=(sqrt{(sqrt{3}-1)^2}+sqrt{3}-1)/2`

`A=(|sqrt{3}-1|+sqrt{3}-1)/2`

`A=(sqrt{3}-1+sqrt{3}-1)/2(` vì `sqrt{3}>1=sqrt{1})`

`A=(2sqrt{3})/2`

`A=sqrt{3}`

Vậy `A=sqrt{3}`