Jup t với mấy bro giỏi giỏi ơi !!!

`Sóc`

`Q+2= (a/{b+c} +1) + (b/{a+c} + 1) + {4c}/{2.\sqrt{2c.(a+b)}}`

`= {c+b+a}/{c+b} + {c+b+a}/{c+a} + {4c}/{2.\sqrt{2c.(a+b)}}`

`= (c+b+a) . (1/{c+b} + 1/{c+a}) + {4c}/{2.\sqrt{2c.(a+b)}}`

`>=` `(c+b+a) . 4/{a+b+2c} + {4c}/{2c+a+b}`

`= {4.(a+b+2c)}/{a+b+2c}=4`

`=> Q` `>=` `2`

Dấu `''=''` xảy ra khi `a=b=c`

Vậy `..............................................`