Giải pt giúp mk vs (2x-1)^3-8x(x-3)(x+3)=-1

`color{#7FFF00}{#Zen n}`

`(2x-1)^3-8x(x-3)(x+3)=-1`

`<=>8x^3-12x^2+6x-1-8x^3+72x=-1`

`<=>8x^3-12x^2+6x-8x^3+72x=-1+1`

`<=>-12x^2+78x=0`

`<=>-6x(2x-13)=0`

`<=>` $\left[\begin{matrix} -6x=0\\ 2x-13=0\end{matrix}\right.$

`<=>` $\left[\begin{matrix} x=0\\ 2x=13\end{matrix}\right.$

`<=>` $\left[\begin{matrix} x=0\\ x=\dfrac{13}{2}\end{matrix}\right.$

Vậy `S={0; 13/2}`