Tìm x: 1/(x - 1) + (-2/3)(3/4 - 6/5) = 5/(2 - 2x)

`1/(x-1) + (-2/3) . (3/4 -6/5) = 5/(2-2x)`

ĐKXĐ: `x ne 1`

`1/(x-1) + (-2/3) . (3/4 -6/5) = 5/(2-2x)`

`<=>  1/(x -1) + (-2/3) . (15/20 - 24/20) =- 5/2 . 1/(x-1)`

`<=> 1/(x -1) + (-2/3) . (-9/20) =- 5/2 . 1/(x-1)`

`<=> 1/(x -1) + 3/10 = -5/2 . 1/(x-1)`

`<=> 1/(x -1) + 5/2 .1/(x-1) = -3/10`

`<=> (1 +5/2) . 1/(x-1) =-3/10`

`<=> 7/2 . 1/(x -1) = -3/10`

`<=> 1/(x -1) = -3/10 . 2/7`

`<=> 1/(x -1) = (-3)/35`

`<=> -3x +3 = 35`

`<=> -3x = 32`

`<=> x = -32/3` (nhận)

Vậy `x = -32/3`