

Tìm x biết
1.3/4+1/5:x=1/4
2.-2x-2/3(3/4-1/8x)=(-1/2)^3
3.(3x+2)(5-x^2)=0
4.|x-1|-|2/3-3/4|=2
5.|x-2/3|-2/5=1/3
6.|x-2|-|1-2x|=0
7.2.3^x-405=3^x-1
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Đáp án:
Giải thích các bước giải:
1. $\frac{3}{4}$ + $\frac{1}{5}$ : x = $\frac{1}{4}$
$\frac{1}{5}$ : x = $\frac{1}{4}$ - $\frac{3}{4}$
$\frac{1}{5}$ : x = $\frac{-1}{2}$
x = $\frac{1}{5}$ : $\frac{-1}{2}$
x = $\frac{-2}{5}$
2. -2x - $\frac{2}{3}$($\frac{3}{4}$ - $\frac{1}{8}$x) = $(\frac{-1}{2})^{3}$
-2x - $\frac{1}{2}$ - $\frac{1}{12}$x = $\frac{-1}{8}$
-2x - $\frac{1}{2}$ = $\frac{-1}{8}$ + $\frac{1}{12}$x
-2x - $\frac{1}{12}$x = $\frac{-1}{8}$ + $\frac{1}{2}$
$\frac{25}{12}$x = $\frac{3}{8}$
x = $\frac{3}{8}$ : $\frac{25}{12}$
x = $\frac{9}{50}$
3. (3x + 2)(5-$x^{2}$)=0
\(\left[ \begin{array}{l}3x+2=0\\ 5-$x^{2}$ = 0\end{array} \right.\)
\(\left[ \begin{array}{l}3x=-2\\$x^{2}$ = 5 \end{array} \right.\)
\(\left[ \begin{array}{l}x=$\frac{-2}{3}$ \\x=$\sqrt{5}$ \end{array} \right.\)
4. |x - 1| - |$\frac{2}{3}$ - $\frac{3}{4}$| = 2
|x-1| - $\frac{1}{12}$ = 2
|x-1| = 2 + $\frac{1}{12}$
|x - 1| = $\frac{25}{12}$
\(\left[ \begin{array}{l}x - 1 = $\frac{25}{12}$ \\x - 1 = $\frac{-25}{12}$\end{array} \right.\)
\(\left[ \begin{array}{l}x=$\frac{37}{12}$ \\x=$\frac{-13}{12}$\end{array} \right.\)
5. |x - $\frac{2}{3}$| - $\frac{-2}{5}$ = $\frac{1}{3}$
|x - $\frac{2}{3}$| = $\frac{1}{3}$ + $\frac{-2}{5}$
|x - $\frac{2}{3}$| = $\frac{1}{15}$
\(\left[ \begin{array}{l}x - $\frac{2}{3}$ = $\frac{1}{15}$\\2 - $\frac{2}{3}$ = $\frac{-1}{15}$\end{array} \right.\)
\(\left[ \begin{array}{l}x=$\frac{11}{15}$ \\x=$\frac{3}{5}$ \end{array} \right.\)
6. |x-2| - |1-2x| = 0
\(\left[ \begin{array}{l}x - 2 = 0\\1 - 2x = 0\end{array} \right.\)
\(\left[ \begin{array}{l}x=2\\2x=1\end{array} \right.\)
\(\left[ \begin{array}{l}x=2\\x=$\frac{1}{2}$ \end{array} \right.\)
7. 2 . $3^{x}$ - 405 = $3^{x-1}$
2 . $3^{x}$ - 405 = $3^{x}$ . $\frac{1}{3}$
2 . $3^{x}$ - $3^{x}$ . $\frac{1}{3}$ =405
$3^{x}$ . (2 - $\frac{1}{3}$) = 405
$3^{x}$ . $\frac{5}{3}$ = 405
$3^{x}$ = 405 : $\frac{5}{3}$
$3^{x}$ = 243
$3^{x}$ = $3^{5}$
x=5
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`1) 3/4 + 1/5 :x = 1/4`
`=> 1/5 : x = 1/4 - 3/4`
`=> 1/5 : x = (-1)/2`
`=> x = 1/5 : (-1)/2`
`=> x = (-2)/5`
Vậy `x = (-2)/5`
`2) -2x - 2/3(3/4-1/8x) = ((-1)/2)^3`
`=> -2x - 1/2 + 1/12 x = (-1)/8`
`=> -2x + 1/12x = (-1)/8 + 1/2`
`=> (-23)/12 x=3/8`
`=> x = (-9)/46`
Vậy `x = (-9)/46`
`3) (3x+2)(5-x^2) = 0`
`=>` \(\left[ \begin{array}{l}3x+2=0\\5-x^2=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}3x=-2\\x^2=5\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=\dfrac{-2}{3}\\x= \pm\sqrt{5}\end{array} \right.\)
Vậy `x in {(-2)/3 ; +- \sqrt{5}`
`4) |x-1| - |2/3 - 3/4| = 0`
`=> |x-1| - |(-1)/12| = 0`
`=> |x-1| - 1/12 = 0`
`=> |x-1| = 1/12`
`=>` \(\left[ \begin{array}{l}x-1=\dfrac{1}{12}\\x-1=\dfrac{-1}{12}\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{13}{12}\\x=\dfrac{11}{12}\end{array} \right.\)
Vậy `x in {13/12 ; 11/12}`
`5) |x - 2/3| - 2/5 = 1/3`
`=> |x - 2/3| = 1/3 + 2/5`
`=> |x-2/3| = 11/15`
`=>` \(\left[ \begin{array}{l}x-\dfrac{2}{3}=\dfrac{11}{15}\\x-\dfrac{2}{3} = \dfrac{-11}{15}\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\dfrac{7}{5}\\x=\dfrac{-1}{15}\end{array} \right.\)
Vậy `x in {7/5 ; (-1)/15}`
`6) |x-2| - |1-2x| = 0`
`=> |x-2| = |1-2x|`
`=>` \(\left[ \begin{array}{l}x-2=1-2x\\x-2=2x-1\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x+2x=2+1\\x-2x=-1+2\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=1\\x=-1\end{array} \right.\)
Vậy `x = +- 1`
`7) 2.3^x - 405 = 3^(x-1)`
`=> 2.3^x - 3^(x-1) = 405`
`=> 2.3^x - 3^x xx 1/3 = 405`
`=> 3^x . (2 - 1/3) = 405`
`=> 3^x. 5/3 = 405`
`=> 3^x = 243`
`=> 3^x = 3^5`
`=> x=5`
Vậy `x=5`
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