giúp em vs ạ!!!!!!!!!!!!

`( 3/2 \sqrt{6} + 2 \sqrt{2/3} - 4 \sqrt{3/2}).( 3 \sqrt{ 2/3} - \sqrt{12} - \sqrt{6} )`

`= ( 3/2 \sqrt{6} + 2 \sqrt{2/3} - 4 \sqrt{3/2}).( \sqrt{3} \sqrt{ 2}- \sqrt{12} - \sqrt{6} )`

`= ( 3/2 \sqrt{6} + 2 \sqrt{2/3} - 4 \sqrt{3/2}).( \sqrt{6}- \sqrt{12} - \sqrt{6} )`

`= ( 3/2 \sqrt{6} + 2 \sqrt{2/3} - 4 \sqrt{3/2}).\sqrt{12}`

`= ( 3/2 \sqrt{6} .\sqrt{12} + 2 \sqrt{2/3}.\sqrt{12}- 4 \sqrt{3/2}.\sqrt{12}`

`= 3/2 . \sqrt{72} + 2. \sqrt{8} - 4 . \sqrt{18}`

`= 3/2 .6\sqrt{2} + 2.2\sqrt{2} - 4.3\sqrt{2}`

`= 9 \sqrt{2} + 4 \sqrt{2} - 12 \sqrt{2}`

`= \sqrt{2}`