mọi người giúp em với ạ

[nm]

`8/(x+2) - 2/(8- x)=(16-2x)/((x+2)(8-x))` `(x` $\ne$ `-2` `;` `x` $\ne$ `8` `)`

`⇔(8(8-x))/((x+2)(8-x)) - (2(x+2))/((8-x)(x+2))=(16-2x)/((x+2)(8-x))`

`⇒8(8-x) - 2(x+2)=16-2x`

`⇔64-8x -2x -4 =16-2x`

`⇔64-4 -8x -2x=16-2x`

`⇔60-10x=16-2x`

`⇔-10x+2x=-60+16`

`⇔-8x=-44`

`⇔x=-44 :(-8)`

`⇔x=44/8=11/2` `(` TM `)`

Vậy `x=11/2`