giải giúp mình với $\frac{2^4.2^6}{(2^5)^2}$ - $\frac{2^5.15^3}{6^3.10^2}$

`(2^4 . 2^6)/(2^5)^2 - (2^5 . 15^3)/(6^3 . 10^2)`

`= (2^4 . 2^6 . 6^3 . 10^2 - 2^5 . 15^3 . (2^5)^2)/((2^5)^2 . 6^3 . 10^2)`

`= (2^10 . 6^3 . 5^2 . 2^2 - 2^5 . 3^3 . 5^3 . 2^10)/(2^10 . 6^3 . 2^2 . 5^2)`

`= (2^10 . 2^3 . 3^3 . 5^2 . 2^2 - 2^5 . 3^3 . 5^3 . 2^10)/(2^10 . 2^3 . 3^3 . 2^2 . 5^2)`

`= (2^15 . 3^3 . 5^2 . (1-5))/(2^15 . 3^3 . 5^2)`

`=-4`