Chỉ cần làm câu e, f thôi ạ

`e)`

`2x^2 +3(x-1)(x+1)=5x(x+1)`

`<=> 2x^2 +3(x^2 -1) = 5x^2 +5x`

`<=> 2x^2 +3x^2 -3 - 5x^2 -5x=0`

`<=> -5x-3=0`

`<=> -5x=3`

`<=>x=-3/5`

Vậy `x=-3/5`.

`f)`

`(8-5x)(x+2)+4(x-2)(x+1)+2(x-2)(x+2)=0`

`<=> -5x^2 -2x+16 + 4(x^2 -x-2) +2(x^2 -4)=0`

`<=> -5x^2 -2x+16+4x^2 -4x -8 + 2x^2 -8=0`

`<=> x^2 -6x=0`

`<=>x(x-6)=0`

`<=>`\(\left[ \begin{array}{l}x=0\\x-6=0\end{array} \right.\) 

`<=>`\(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\) 

Vậy `x=0;x=6`.