giup em voi em cam on nnha di ạ huhuhu

$a/$

$2Al+6HCl \to 2AlCl_3+3H_2$

$Zn+2HCl \to ZnCl_2+H_2$

$n_{H_2}=\frac{13,44}{22,4}=0,6(mol)$

$n_{Al}=a(mol)$

$n_{Zn}=b(mol)$

$m_{hh}=27a+65b=24,9(1)$

$n_{H_2}=1,5a+1b=0,6(2)$

$(1)(2)$

$a=0,2; b=0,3$

$b/$

$\%m_{Al}=\frac{0,2.27}{24,9}.100\%=21,69\%$

$\%m_{Zn}=78,31\%$

$c/$

$m_{ddHCl}=\frac{1,2.36,5.100}{14,6}=300(g)$

$m_{dd}=24,6+300-0,6.2=323,4\%$

$\%m_{AlCl_3}=\frac{0,2.133,5}{323,4}.100\%=8,26\%$
$\%m_{ZnCl_2}=\frac{0,3.136}{323,4}.100\%=12,62\%$