Cho đa thức P(x) = x^3 + ax^2 + bx + c . Biết P(1) = 15 ; P(2) = 30 . Tính P(3) - P(0)

Ta có: `P(1)=15`

`=>` `a+b+c=15`

Ta có: `P(2)=30`

`=>` `4a+2b+8+c=30`

`=>` `4a+2b+c=22`

Ta có: `P(3)-P(0)`

`=9a+3b+c+27-c`

`=9a+3b+27`

`=3(3a+b+9)`

`=3(3a+b+15-6)`

`=3(3a+b+a+b+c-6)`

`=3(4a+2b+c-6)`

`=3(22-6)`

`=48`

Vậy `P(3)-P(0)=48`

$\\$

`\bb\color{#3a34eb}{\text{@hoanganhnguyen09302}}`