y x 2/3 + y x 1/6 = 10/3

$y^{}$ x $\frac{2}{3}$ + $y^{}$ x$\frac{1}{6}$ = $\frac{10}{3}$

y x $\frac{4}{6}$ + y x$\frac{1}{6}$ = $\frac{20}{6}$

y x ($\frac{4}{6}$ + $\frac{1}{6}$) = $\frac{20}{6}$

y x $\frac{5}{6}$ = $\frac{20}{6}$

y = 4