Giải chi tiết giúp e với ạ

Em tham khảo nha:

\(\begin{array}{l}
a)\\
{C_6}{H_{12}}{O_6} \xrightarrow{\text{ lên men }} 2{C_2}{H_5}OH + 2C{O_2}\\
{n_{{C_6}{H_{12}}{O_6}}} = \dfrac{{90}}{{180}} = 0,5\,mol\\
{n_{{C_2}{H_5}OH}} = 2{n_{{C_6}{H_{12}}{O_6}}} = 1\,mol\\
{V_{{C_2}{H_5}OH}} = \dfrac{{1 \times 46}}{{0,8}} = 57,5ml\\
b)\\
{n_{C{O_2}}} = 2{n_{{C_6}{H_{12}}{O_6}}} = 1\,mol\\
{V_{C{O_2}}} = 1 \times 22,4 = 22,4l\\
c)\\
H = 65\%  \Rightarrow {V_{{C_2}{H_5}OH}} = 57,5 \times 65\%  = 37,375ml
\end{array}\)