Thực hiện dãy chuyển hóa sa: a) C2H4 --> C2H6 ---> C2H5OH --> CH3COOH --> CH3COONa --> CH4 b) CH4 --> C2H2 ---> C2H4 ---> C2H5OH --> CH3COOH --> CH3COONa c) C2H4 --> C2H5OH --> CH3COOH ---> CH3COOC2H5 ---> CH3COONa

Đáp án `+` Giải thích các bước giải:

$\rm a)$
$\rm C_2H_4 + H_2 \xrightarrow{Ni,t^o} C_2H_6$
$\rm C_2H_6 + Cl_2 \xrightarrow{a/s} C_2H_5Cl + HCl$
$\rm C_2H_5Cl + NaOH \xrightarrow{t^o} C_2H_5OH + NaCl$

$\rm C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O$
$\rm CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O$
$\rm CH_3COONa + NaOH \xrightarrow{CaO,t^o} CH_4 \uparrow + Na_2CO_3$
$\rm b)$
$\rm 2CH_4 \xrightarrow[\text{làm lạnh nhanh}]{1500^oC} C_2H_2 + 3H_2$
$\rm C_2H_2 + H_2 \xrightarrow[t^o]{Pd/PbCO_3} C_2H_4$
$\rm C_2H_4 + H_2O \xrightarrow{Axit,t^o} C_2H_5OH$
$\rm C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O$
$\rm CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O$

$\rm c)$
$\rm C_2H_4 + H_2O \xrightarrow{Axit,t^o} C_2H_5OH$
$\rm C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O$

$\rm CH_3COOH + C_2H_5OH \buildrel{{H_2SO_{4(đặc)},t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$

$\rm CH_3COOC_2H_5 + NaOH \xrightarrow{t^o} CH_3COONa + C_2H_5OH$