Bài 3: Viết các phương trình hóa học theo sơ đồ biến đổi sau: a) C6H12O6 C2H5OH CH3COOH CH3COOC2H5CH3COOK b) C2H4 C2H5OH CH3COOH CH3COOC2H5CH3COOK c) C4H10 CH3COOH CH3COOC2H5 C2H5OH C2H5OK

Đáp án `+` Giải thích các bước giải:

$\rm a)$
$\rm C_6H_{12}O_6 \xrightarrow[30-35^oC]{\text{men rượu}} 2C_2H_5OH + 2CO_2$
$\rm C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O$
$\rm CH_3COOH + C_2H_5OH \buildrel{{H_2SO_{4(đặc)},t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$

$\rm CH_3COOC_2H_5 + KOH \xrightarrow{t^o} CH_3COOK + C_2H_5OH$
$\rm b)$
$\rm C_2H_4 + H_2O \xrightarrow{axit,t^o} C_2H_5OH$
$\rm C_2H_5OH + O_2 \xrightarrow{\text{men giấm}} CH_3COOH + H_2O$
$\rm CH_3COOH + C_2H_5OH \buildrel{{H_2SO_{4(đặc)},t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$

$\rm c)$
$\rm 2C_4H_{10} + 5O_2 \xrightarrow{t^o} 4CH_3COOH + 2H_2O$

$\rm CH_3COOH + C_2H_5OH \buildrel{{H_2SO_{4(đặc)},t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$

$\rm CH_3COOC_2H_5 + KOH \xrightarrow{t^o} CH_3COOK + C_2H_5OH$

$\rm 2C_2H_5OH + 2K \rightarrow 2C_2H_5OK + H_2$