tính A +(-2/3) ^2 .2023 + (-4/9).2022 +(3/2)^2 TÌM X 2x=3/2x+25% tìm x n |x-4|-|x+1|+-1 mong mn giúp

Đáp án:

$\begin{array}{l}
A = {\left( { - \dfrac{2}{3}} \right)^2}.2023 + \left( { - \dfrac{4}{9}} \right).2022 + {\left( {\dfrac{3}{2}} \right)^2}\\
 = \dfrac{4}{9}.2023 - \dfrac{4}{9}.2022 + \dfrac{9}{4}\\
 = \dfrac{4}{9}.\left( {2023 - 2022} \right) + \dfrac{9}{4}\\
 = \dfrac{4}{9}.1 + \dfrac{9}{4}\\
 = \dfrac{4}{9} + \dfrac{9}{4}\\
 = \dfrac{{97}}{{36}}\\
b)\\
2x = \dfrac{3}{2}.x + 25\% \\
 \Leftrightarrow 2x - \dfrac{3}{2}.x = \dfrac{{25}}{{100}}\\
 \Leftrightarrow \left( {2 - \dfrac{3}{2}} \right).x = \dfrac{1}{4}\\
 \Leftrightarrow \dfrac{1}{2}.x = \dfrac{1}{4}\\
 \Leftrightarrow x = \dfrac{1}{4}:\dfrac{1}{2}\\
 \Leftrightarrow x = \dfrac{1}{2}\\
\end{array}$