2x mũ 3. +5x mũ 2- 3x =0

`2x^3+5x^2-3x=0`

`=>x(2x^2+5x-3)=0`

`=>x(2x-1)(x+3)=0`

`=>` \(\left[ \begin{array}{l}x=0\\2x-1=0\\x+3=0\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=0\\x=\dfrac{1}{2}\\x=-3\end{array} \right.\) 

Vậy `S={-3;0;1/2}`