

Hãy luôn nhớ cảm ơn và vote 5*
nếu câu trả lời hữu ích nhé!
`B=1/3-2/3^2+3/3^3-4/3^4+...+2021/3^2021-2022/3^2022`
`3B=1-2/3+3/3^2-4/3^3+...+2021/3^2020-2022/3^2021`
`3B+B=(1-2/3+3/3^2-4/3^3+...+2021/3^2020-2022/3^2021)+(1/3-2/3^2+3/3^3-4/3^4+...+2021/3^2021-2022/3^2022)`
`4B=1-1/3+1/3^2-1/3^3+...+1/3^2020-1/3^2021-2022/3^2022`
`12B=3-1+1/3-1/3^2+...+1/3^2019-1/3^2020-2022/3^2021`
`12B+4B=(3-1+1/3-1/3^2+...+1/3^2019-1/3^2020-2022/3^2021)+(1-1/3+1/3^2-1/3^3+...+1/3^2020-1/3^2021-2022/3^2022)`
`16B=3-2023/3^2021-2022/3^2022<3`
`=>B<3:16=3/16`
Vậy `B<3/16`(đpcm)
Hãy giúp mọi người biết câu trả lời này thế nào?

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