ai giúp mik với ạ mik đng cần gấp plsssss

Đáp án:

$c)0.$

Giải thích các bước giải:

$c) \left(\dfrac{0,4-\dfrac{2}{9}+\dfrac{2}{11}}{1,4-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-0,25+\dfrac{1}{5}}{1\dfrac{1}{6}-0,875+0,7}\right):\dfrac{2022}{2023}\\ =\left(\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{\dfrac{7}{6}-\dfrac{7}{8}+\dfrac{7}{10}}\right):\dfrac{2022}{2023}\\ =\left[\dfrac{2\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}{7\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{11}\right)}-\dfrac{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}{\dfrac{7}{2}\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}\right)}\right]:\dfrac{2022}{2023}\\ =\left[\dfrac{2}{7}-\dfrac{1}{\dfrac{7}{2}}\right]:\dfrac{2022}{2023}\\ =\left[\dfrac{2}{7}-\dfrac{2}{7}\right]:\dfrac{2022}{2023}\\ =0:\dfrac{2022}{2023}\\ =0.$