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Đáp án:

\(118.\)

\(n_{CO_2^{}}^{} = \frac{{8,4}}{{22,4}} = 0,375\,mol\)

\(m_X^{} = m_C^{} + m_H^{}\)

\( \to 6 = 0,375.12 + m_H^{}\)

\( \to m_H^{} = 1,5\,gam\)

\(n_H^{} = \frac{{1,5}}{1} = 1,5\,mol\)

\(C:H = 0,375:1,5 = 1:4\)

\( \to CTHH:CH_4^{}\)

\(119.\)

\(n_X^{} = \frac{{0,224}}{{22,4}} = 0,01\,mol\)

\(n_{H_2^{}O}^{} = \frac{{0,672}}{{22,4}} = 0,03\,mol\)

\(n_H^{} = 0,03.2 = 0,06\,mol\)

\(H = \frac{{n_H^{}}}{{n_X^{}}} = \frac{{0,06}}{{0,01}} = 6\)

\( \to C_2^{}H_6^{}\)